x^2+2x+y^2+4y=20

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Solution for x^2+2x+y^2+4y=20 equation: 


Simplifying
x2 + 2x + y2 + 4y = 20

Reorder the terms:
2x + x2 + 4y + y2 = 20

Solving
2x + x2 + 4y + y2 = 20

Solving for variable 'x'.

Reorder the terms:
-20 + 2x + x2 + 4y + y2 = 20 + -20

Combine like terms: 20 + -20 = 0
-20 + 2x + x2 + 4y + y2 = 0

The solution to this equation could not be determined.

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